# How do you find #dy/dx# by implicit differentiation of #y=sin(xy)#?

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To find dy/dx by implicit differentiation of y = sin(xy), apply the chain rule and product rule. First, differentiate both sides of the equation with respect to x. The derivative of sin(xy) with respect to x is cos(xy) * (y + x * dy/dx). Then solve for dy/dx. So, dy/dx = (cos(xy) * y + cos(xy) * x * dy/dx) / (cos(xy) * x - sin(xy)). Finally, isolate dy/dx to get the result.

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