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How do you find #(d^2y)/(dx^2)# given #x^2-xy=5#?

Answer 1

Paisley Johnson

# -10/x^3#

From #x^2-xy=5# we know that

#y =( x^2-5)/x# then

#dy/(dx) = 1+5/x^2# and following

#(d^2y)/(dx^2) = -10/x^3#

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Answer 2

Isaiah Allen

To find (\frac{{d^2y}}{{dx^2}}) given (x^2-xy=5), first differentiate the equation implicitly with respect to (x) to find (\frac{{dy}}{{dx}}), and then differentiate (\frac{{dy}}{{dx}}) with respect to (x) to find (\frac{{d^2y}}{{dx^2}}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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