How do you find antiderivative of #(1-x)^2#?
By signing up, you agree to our Terms of Service and Privacy Policy
To find the antiderivative of (1-x)^2, you can use the power rule for integration. The antiderivative of (1-x)^2 with respect to x is:
∫(1-x)^2 dx = ∫(1 - 2x + x^2) dx = x - x^2/2 + x^3/3 + C
Where C is the constant of integration.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you evaluate the integral #int sec^2x/(sqrt(1-tanx))dx# from 0 to #pi/4#?
- How do you evaluate the integral #int sinx/(1+x^2)# from #-oo# to #oo#?
- How do you find the integral of #cos^5(3x)dx#?
- How do you evaluate the definite integral #int2xdx# from #[0,1]#?
- How do you evaluate the definite integral #int (14x^6)dx# from [-2,2]?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7