# How do you find an equation of the tangent line to the graph of y = g(x) at x = 5 if g(5) = -3 and g’(5) = 4?

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To find the equation of the tangent line to the graph of y = g(x) at x = 5, we can use the point-slope form of a linear equation.

The point-slope form is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Given that g(5) = -3 and g’(5) = 4, we have the point (5, -3) on the tangent line and the slope of the tangent line is 4.

Using the point-slope form, the equation of the tangent line is y - (-3) = 4(x - 5).

Simplifying this equation gives y + 3 = 4x - 20.

Therefore, the equation of the tangent line to the graph of y = g(x) at x = 5 is y = 4x - 23.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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