# How do you find an equation of the tangent line to the curve at the given point: #y = csc (x) - 2 sin (x)# and P = (pi/6, 1)?

The equation is

Start by differentiating the function.

Now, find the slope of the tangent.

We now find the equation of the tangent line with our point and our slope.

Hopefully this helps!

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To find the equation of the tangent line to the curve at the given point (pi/6, 1), we need to find the derivative of the function y = csc(x) - 2sin(x) and evaluate it at x = pi/6.

The derivative of y = csc(x) - 2sin(x) can be found using the chain rule and product rule.

The derivative is given by: dy/dx = -csc(x)cot(x) - 2cos(x)

Evaluating the derivative at x = pi/6, we have: dy/dx = -csc(pi/6)cot(pi/6) - 2cos(pi/6)

Simplifying further, we get: dy/dx = -2 - 2√3

Now, we have the slope of the tangent line at the point (pi/6, 1).

Using the point-slope form of a line, the equation of the tangent line is: y - 1 = (-2 - 2√3)(x - pi/6)

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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