How do you find an equation of the line with slope 3 that contains the point (4, 1)?
Substituting the values of h, k and m in the Point-Slope form, we get
We get the equation of the line as :
The graph will look like this:
graph{ y=3x - 11 [-10, 10, -5, 5]}
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To find the equation of a line with a given slope and passing through a given point, you can use the point-slope form of a linear equation. The point-slope form is:
y - y1 = m(x - x1)
Where (x1, y1) is the given point, m is the slope of the line.
Using the point (4, 1) and slope 3:
y - 1 = 3(x - 4)
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the slope of any line perpendicular to the line passing through #(2,15)# and #(10,21)#?
- What is the equation in point-slope form and slope intercept form for the line given slope= -1/2, (0,3)?
- How do you the equation of the line that passes through point (-2, 3) and is parallel to the line formed by the equation y = 4x + 7?
- The pair of points lies on the same line with the given slope. Find X? (5,14), (X, 23); slope = 3
- How do you write an equation of a line given (-6,5) and m=0?

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