# How do you find an equation of the line that contains the given point and is parallel to the given line (-9,61), y= -6x 10?

Since the new line is parallel, the slope is also

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To find an equation of the line that contains the point (-9,61) and is parallel to the line y = -6x + 10, you use the fact that parallel lines have the same slope. So, the slope of the new line will also be -6. Then, you use the point-slope form of a linear equation, y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope. Plugging in the values, you get the equation y - 61 = -6(x + 9). Simplify to get the final equation in slope-intercept form if needed.

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To find the equation of a line parallel to the given line (y = -6x + 10) and passing through the point ((-9, 61)), we use the fact that parallel lines have the same slope.

The slope of the given line (y = -6x + 10) is (-6). So, the slope of the parallel line will also be (-6).

Now, using the point-slope form of a linear equation (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the given point, we substitute (m = -6) and ((x_1, y_1) = (-9, 61)):

(y - 61 = -6(x + 9))

Now, simplify and rewrite in slope-intercept form (y = mx + b):

(y - 61 = -6x - 54)

(y = -6x - 54 + 61)

(y = -6x + 7)

So, the equation of the line parallel to (y = -6x + 10) and passing through the point ((-9, 61)) is (y = -6x + 7).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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