# How do you find an equation of the line perpendicular to the graph of 15x-5y=7 that passes through the point at (0,-4)?

The equation of the perpendicular line is

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To find the equation of a line perpendicular to the graph of (15x - 5y = 7) and passing through the point ((0, -4)), you need to determine the slope of the given line first. Then, since perpendicular lines have slopes that are negative reciprocals, you can find the slope of the perpendicular line. Finally, you can use the point-slope form of a line to find the equation of the perpendicular line.

- Find the slope of the given line (15x - 5y = 7) by rearranging it into slope-intercept form ((y = mx + b)).
- Once you have the slope of the given line, find the negative reciprocal to get the slope of the perpendicular line.
- Use the point-slope form ((y - y_1) = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the given point, to find the equation of the perpendicular line. Use the given point ((0, -4)) and the slope you found in step 2 to complete the equation.

This process will give you the equation of the line perpendicular to the given line that passes through the point ((0, -4)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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