How do you find all the zeros of #(3x^6+x^24)(x^3+6x+7)#?
This product has zeros:

#1# 
#1# (with multiplicity#2# ) 
#+(sqrt((4sqrt(3)3)/12))+(sqrt((4sqrt(3)+3)/12))i# 
#1/2+(3sqrt(3))/2 i#
We find:
(see https://tutor.hix.ai)
So:
Hence:
The remaining quadratic factor has zeros given by the quadratic formula:
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To find all the zeros of the expression (3x^6 + x^2  4)(x^3 + 6x + 7), you first need to find the zeros of each factor separately, as the zeros of the product are the combined zeros of the individual factors.

For the first factor 3x^6 + x^2  4, you can factorize it further if possible and find its zeros by setting it equal to zero and solving for x.

For the second factor x^3 + 6x + 7, you can also find its zeros by setting it equal to zero and solving for x.
The combined set of zeros for both factors will be the zeros of the given expression.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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