How do you find all points of inflection given #y=-(x+2)^(2/3)#?
Charles ArochaThere are no points of inflection.
The concavity does not change, so there are no inflection points.
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Adam AdkinsTo find points of inflection, find the second derivative, set it equal to zero, and solve for x. Then, determine the corresponding y-values.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- If #y= x^3 + 6x^2 + 7x -2cosx#, what are the points of inflection of the graph f (x)?
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- How do you determine whether the function #f(x)= 5+12x- x^3# is concave up or concave down and its intervals?
- How do you find the inflection points for the function #f(x)=e^sin(x)#?
- How do you find the interval where f is concave up and where f is concave down for #f(x)= –(2x^3)–(3x^2)–7x+2#?
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