# How do you find all points of inflection given #y=-sin(2x)#?

Points of inflection would occur every

To find points of inflection, we need to find all the points on the graph at which the second derivatives will have a value of 0:

Using chain rule:

Using same principles to differentiate again:

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To find the points of inflection for ( y = -\sin(2x) ), you need to find the second derivative of the function, set it equal to zero, and solve for ( x ). Then, determine the corresponding ( y ) values for those ( x ) values.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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