How do you find a standard form equation for the line with slope -3 that contains the point (6,8)?

Answer 1

Julia Adams

#3x +y =26#

According to the slope point form,

#y-y_1 = m(x-x_1)#

#y-8 = -3(x-6)#

#y-8 = -3x+18)#

#3x +y -8=18#

#3x +y =26#

Standard form is #ax + by =c# where # a, b and c# are integers and #a >0#

General from is #ax +by + c =0#

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Answer 2

Hazel Anglin

To find the standard form equation for the line with slope -3 that contains the point (6,8), you can use the point-slope form of a linear equation, which is ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. Substituting the given values, you get ( y - 8 = -3(x - 6) ). Expanding this equation, you get ( y - 8 = -3x + 18 ). Simplifying further, you get ( y = -3x + 26 ). Finally, rearrange the equation to standard form, which is ( 3x + y = 26 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.