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How do you find a standard form equation for the line (0,2) (2,2)?

Answer 1

Eva Adamson

#y=2#

Using a different approach but gives the same answer as Noobs

Let point 1 be #P_1->(x_1,y_1) = (0,2)#
Let point 2 be #P_2->(x_2,y_2)=(2,2)#

Using standard equation form:#" "y=mx+c#

where #m-> "gradient"#

#m->("change in y-axis")/("change in x-axis") = (y_2-y_1)/(x_2-x_1) = (2-2)/(2-0) = 0/2 = 0#

As the gradient is 0 there is no change up or down so the graph is that of a horizontal line ( parallel to the x-axis).

Thus the equation of the line is the value of y which is 2 so we have:

#y=2#

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Answer 2

Eva Abramson

To find the standard form equation for the line passing through the points (0,2) and (2,2), first, calculate the slope using the formula: slope = (y2 - y1) / (x2 - x1). Then, use the point-slope form of a linear equation, y - y1 = m(x - x1), where (x1, y1) is one of the given points and m is the slope. Finally, rearrange the equation into the standard form Ax + By = C.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.