How do you find a set of two consecutive integers whose sum is equal to the next integer immediately following them?

Answer 1

The numbers are #1# and #2#.

Let the smallest number be #x#, the middle number be #x + 1# and the larger number be #x + 2#.
Then, #x + x + 1 = x + 2#.
#2x + 1 = x + 2#
#x = 1#
#:.# The numbers are #1# and #2#.

Hopefully this helps!

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

Let the two consecutive integers be (n) and (n+1). The sum of these integers is (n + (n+1)), and the next integer immediately following them is (n+2). Set up the equation:

[ n + (n+1) = n+2 ]

Solve for (n).

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7