How do you find a Power Series solution of a partial differential equation?

Answer 1
Let us solve #y''+y=0# by Power Series Method.
Let #y=sum_{n=0}^inftyc_nx^n#, where #c_n# is to be determined.

By taking derivatives,

#y'=sum_{n=1}^inftync_nx^{n-1} Rightarrow y''=sum_{n=2}^inftyn(n-1)c_nx^{n-2}#
We can rewrite #y''+y=0# as
#sum_{n=2}^inftyn(n-1)c_nx^{n-2}+sum_{n=0}^inftyc_nx^n=0#

by shifting the indices of the first summation by 2,

#Rightarrow sum_{n=0}^infty(n+2)(n+1)c_{n+2}x^n+sum_{n=0}^inftyc_nx^n=0#

by combining the summations,

#Rightarrow sum_{n=0}^infty[(n+2)(n+1)c_{n+2}+c_n]x^n=0#,
#Rightarrow (n+2)(n+1)c_{n+2}+c_n=0#
#Rightarrow c_{n+2}=-{c_n}/{(n+2)(n+1)}#

Let us look at even coefficients.

#c_2={-c_0}/{2cdot1}=-c_0/{2!}# #c_4={-c_2}/{4cdot3}={-1}/{4cdot3}cdot{-c_0}/{2!}=c_0/{4!}# #c_6={-c_4}/{6cdot5}={-1}/{6cdot5}cdot c_0/{4!}=-{c_0}/{6!}# . . . #c_{2n}=(-1)^n{c_0}/{(2n)!}#

Let us look at odd coefficients.

#c_3={-c_1}/{3cdot2}=-{c_1}/{3!}# #c_5={-c_3}/{5cdot4}={-1}/{5cdot4}cdot{-c_1}/{3!}={c_1}/{5!}# #c_7={-c_5}/{7cdot6}={-1}/{7cdot6}cdot{c_1}/{5!}=-{c_1}/{7!}# . . . #c_{2n+1}=(-1)^n{c_1}/{(2n+1)!}#

Hence, the solution can be written as:

#y=sum_{n=0}^inftyc_nx^n#

by splitting into even terms and odd terms,

#=sum_{n=0}^inftyc_{2n}x^{2n}+sum_{n=0}^inftyc_{2n+1}x^{2n+1}#
by pluggin in the formulas for #c_{2n}# and #c_{2n+1}# we found above,
#=c_0sum_{n=0}^infty(-1)^n{x^{2n}}/{(2n)!}+c_1 sum_{n=0}^infty(-1)^n{x^{2n+1}}/{(2n+1)!}#

By recognizing the power series,

#y=c_0 cosx+c_1 sinx#

I hope that this was helpful.

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Answer 2

To find a power series solution of a partial differential equation (PDE), follow these steps:

  1. Express the solution as a power series: Assume that the solution ( u(x, y) ) can be written as a power series in ( x ) and ( y ):

[ u(x, y) = \sum_{n=0}^\infty \sum_{m=0}^\infty a_{nm}x^n y^m ]

  1. Substitute the power series into the PDE: Replace ( u(x, y) ) and its derivatives in the PDE with their corresponding power series expansions.

  2. Equate coefficients of like powers of ( x ) and ( y ): Match coefficients of like powers of ( x ) and ( y ) on both sides of the PDE.

  3. Solve the resulting system of algebraic equations: Solve the system of equations obtained by equating coefficients.

  4. Determine the convergence of the solution: Analyze the convergence of the power series solution, considering the radius of convergence.

  5. Verify the solution: Substitute the power series solution back into the original PDE to ensure it satisfies the equation.

  6. Apply boundary or initial conditions: If boundary or initial conditions are given, apply them to determine the values of the coefficients in the power series solution.

  7. Check for uniqueness: Ensure that the power series solution is unique within the given boundary or initial conditions.

By following these steps, you can find a power series solution of a partial differential equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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