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How do you find a line that passes through a point (3,1) that is parallel to a line whose slope is -1/2?

Answer 1

Isaiah Anthony

#y=-1/2x+5/2#

parallel lines have equal slopes so the equation of the line is : #y=-1/2x+C#

We can replace the point (3,1) in the since it is on the line.

equation above to find #C# ;

#1=-1/2(3)+C# , #1=-3/2+C# , #1+3/2=C# , #C=5/2#

the overall equation is #y=-1/2x+5/2#

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Answer 2

Isaiah Anthony

To find a line passing through a point (3,1) that is parallel to a line with a slope of -1/2, you use the fact that parallel lines have the same slope. Therefore, the slope of the new line will also be -1/2. Then, you use the point-slope form of a linear equation, y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope. Plug in the values (3,1) for (x₁, y₁) and -1/2 for the slope (m) to find the equation of the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.