How do you find a formula for the sequence -2, 1, 6, 13, 22..?

Answer 1

The sequence can be written in a recursive way:

#a_0=-2#, #a_n=a_(n-1)+(2n+1)#.

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Answer 2

The sequence you provided is generated by adding consecutive odd integers to the previous term starting from 1.

The formula for the nth term of this sequence can be expressed as: [a_n = n^2 - 3] where (a_n) represents the nth term of the sequence.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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