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How do you find 3 consecutive odd integers such that the sum of the first and third is 14?

Answer 1

I found #5,7,9#

I would call the integers: #2n+1# #2n+3# #2n+5# so you get that: #(2n+1)+(2n+5)=14# #4n+6=14# #4n=8# so #n=2# and your integers will be: #2n+1=5# #2n+3=7# #2n+5=9#

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Answer 2

Ethan Adkins

Let ( x ) represent the first odd integer. Then the next two consecutive odd integers are ( x + 2 ) and ( x + 4 ).

Since the sum of the first and third integers is 14, we can set up the equation ( x + (x + 4) = 14 ).

Solve for ( x ): [ x + x + 4 = 14 ] [ 2x + 4 = 14 ] [ 2x = 10 ] [ x = 5 ]

So, the first odd integer is 5, and the consecutive odd integers are 5, 7, and 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.