Home > Algebra > Addition and Subtraction of Polynomials

How do you find #2p^2 + 3p - 4# less #- 2p^2 - 3p + 4#?

Answer 1

Eva Adamson

#2p^2 + 3p - 4# less #- 2p^2 - 3p + 4# is
#2(2p^2+3p-4)#.

The expression you wrote means #2p^2 + 3p - 4 - (- 2p^2 - 3p + 4)=# #2p^2+3p-4+2p^2+3p-4=# #4p^2+6p-8=# #2(2p^2+3p-4)#.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Avery Alexander

To find the result of (2p^2 + 3p - 4) minus (-2p^2 - 3p + 4), you can perform subtraction by combining like terms:

[ (2p^2 + 3p - 4) - (-2p^2 - 3p + 4) ]

[ = 2p^2 + 3p - 4 + 2p^2 + 3p - 4 ]

[ = (2p^2 + 2p^2) + (3p + 3p) + (-4 - 4) ]

[ = 4p^2 + 6p - 8 ]

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.