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How do you factor #y= x^2 + 3x - 10 #?

Answer 1

Isaiah Anthony

#y = x^2+3x-10 = (x+5)(x-2)#

Find a pair of factors of #10# which differ by #3#.

The pair #5, 2# works, hence:

#x^2+3x-10 = (x+5)(x-2)#

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Answer 2

Abigail Allen

To factor the quadratic equation (y = x^2 + 3x - 10), you need to find two numbers that multiply to the constant term (-10) and add up to the coefficient of the linear term (3). These numbers are 5 and -2. Then, rewrite the middle term using these numbers and factor by grouping. Thus, the factored form of (y = x^2 + 3x - 10) is ((x + 5)(x - 2)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.