How do you factor #x^3 + x^2 + x - 3#?

Answer 1

First, you know that #x=1# is a root because ...

#1+1+1-3=0#

So, divide the function by #(x-1)# using synthetic or long division to get ...
#x^2+2x+3#

Now, this function has only imaginary roots, so use the quadratic formula ...

#x=[-2+-sqrt(2^2-4(1)(3))]/(2(1))=-1+-isqrt2#

In summary, here are the factors:

#(x-1)(x+1-isqrt2)(x+1+isqrt2)#

hope that helped

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Answer 2

To factor (x^3 + x^2 + x - 3), you can use the rational root theorem or synthetic division to find its roots, then use those roots to factor it completely.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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