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How do you factor # x^3 + 8x^2 = -16x #?

Answer 1

Avery Alexander

First you take everything to one side (by adding #16x# to both sides)

#->x^3+8x^2+16x=0#

You can take out #x# from all terms: #->x(x^2+8x+16)=0#

The quadratic part should be easy to factor: #->x(x+4)^2=0#

Solution: #x=0orx=-4#

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Answer 2

Nathan Axel

To factor the equation (x^3 + 8x^2 = -16x), you can start by rearranging it to (x^3 + 8x^2 + 16x = 0). Then, factor out the common factor (x), resulting in (x(x^2 + 8x + 16) = 0). Now, you can factor the quadratic expression inside the parentheses, which gives you (x(x + 4)^2 = 0). Thus, the factored form of the equation is (x(x + 4)^2 = 0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.