How do you factor #x^2 - x - 12?#?

Answer 1

We can Split the Middle Term of this expression to factorise it

In this technique, if we have to factorise an expression like #ax^2 + bx + c#, we need to think of 2 numbers such that:
#N_1*N_2 = a*c = 1*-12 = -12# AND #N_1 +N_2 = b = -1#
After trying out a few numbers we get #N_1 = 3# and #N_2 =-4#
#3*-4 = -12#, and #3+(-4)= -1#
#x^2 - x - 12 = x^2 +3x - 4x - 12#
# = x(x+3) - 4(x+3)#
#x+3# is a common factor to each of the terms
#=color(green)((x+3)(x-4)#
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Answer 2

To factor the expression (x^2 - x - 12), you can use the method of factoring by grouping or the quadratic formula. In this case, the expression factors as ((x - 4)(x + 3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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