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How do you factor #x^2 - 4x + 4 =0#?

Answer 1

Savannah Anderson

#(x-2)(x-2) = 0#
#x = 2#

To factor the expression you need to find factors of 4 which add up to 4.

The signs will be the same (because of +4), they are both minus (because of -4x).

#2 xx2 = 4 and 2 + 2 = 4#

#(x-2)(x-2) = 0#

Now that we have the factors, we can solve: If #x - 2 =0", then "x =2#

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Answer 2

Nathan Axel

To factor the quadratic equation (x^2 - 4x + 4 = 0), you need to find two numbers that multiply to (4) and add up to (-4). Since the constant term (4) is a perfect square and the coefficient of (x) is (2), the equation is a perfect square trinomial. Therefore, it factors as ((x - 2)^2 = 0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.