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How do you factor #x^2-15x+36#?

Answer 1

Eli Assouline

#(x-12)(x-3)#

#"the factors of + 36 which sum to - 15 are - 12 and - 3"#

#rArrx^2-15x+36=(x-12)(x-3)#

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Answer 2

Kennedy Adams

Use middle term splitting.
#x^2-15x+36=(x-3)(x-12)#

Spli the middle term such that the product of terms should be +36 and sum (-15). So, check the factors of 36 which satisfies this condition. Factors of 36 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 36 Since sum should be negative and product should be positive, both factors should be negative. Thus the required pair of factors is -3 and -12.

#x^2-15x+36=x^2-3x-12x+36# (Split the middle term)

#=x(x -3)-12(x-2)# #=(x-3)(x-12)#

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Answer 3

Ethan Adkins

To factor the quadratic expression (x^2 - 15x + 36), we need to find two numbers that multiply to (36) and add up to (-15). These numbers are (-3) and (-12). So, the factored form of (x^2 - 15x + 36) is ((x - 3)(x - 12)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.