# How do you factor #(x^2-14x+49)/(x^2-2x-35)#?

The numerator is a squared bynomial:

the denominator is similar to a trynomial of the type

where you can find two numbers whose sum is s and whose product is p, in this case the numbers are -7 and 5 because

-7+5=-2 and -7*5=-35

so

now you can rewrite the fraction:

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To factor the expression (x^2-14x+49)/(x^2-2x-35), we can first factor the numerator and denominator separately.

The numerator, x^2-14x+49, can be factored as (x-7)(x-7) or (x-7)^2.

The denominator, x^2-2x-35, can be factored as (x-7)(x+5).

Therefore, the expression can be simplified as (x-7)^2/(x-7)(x+5).

Simplifying further, we can cancel out the common factor of (x-7) from the numerator and denominator, resulting in (x-7)/(x+5).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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