How do you factor #x² - 14x + 9#?

Answer 1

Nathan Axel

#x^2-14x+9=(x-7-2sqrt(10))(x-7+2sqrt(10))#

One way is to complete the square and use the difference of squares identity:

#a^2-b^2=(a-b)(a+b)#

with #a=(x-7)# and #b=2sqrt(10)# as follows:

#x^2-14x+9#

#=(x-7)^2-7^2+9#

#=(x-7)^2-40#

#=(x-7)^2-2^2*10#

#=(x-7)^2-(2sqrt(10))^2#

#=((x-7)-2sqrt(10))((x-7)+2sqrt(10))#

#=(x-7-2sqrt(10))(x-7+2sqrt(10))#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Genesis Allen

To factor the expression x² - 14x + 9, you need to find two numbers that multiply to give 9 (the constant term) and add to give -14 (the coefficient of the linear term). These numbers are -9 and -1. Therefore, the factored form of x² - 14x + 9 is (x - 9)(x - 1).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.