How do you factor the trinomial # x^2- 2x - 8#?
Select the numbers from the factors of 8 possible factors are 2 and 4 which has a difference of 2 with a product of 8.
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To factor the trinomial ( x^2 - 2x - 8 ), you need to find two numbers that multiply to the last term ((-8)) and add up to the middle coefficient ((-2)). Those numbers are (-4) and (2). Rewrite the trinomial as (x^2 - 4x + 2x - 8), then factor by grouping: (x(x - 4) + 2(x - 4)). Factor out the common factor of (x - 4), resulting in ((x - 4)(x + 2)). So, (x^2 - 2x - 8) factors to ((x - 4)(x + 2)).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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