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How do you factor the trinomial #x^2 + 11x - 28#?

Answer 1

#(x+(11+sqrt(233))/2)(x-(-11+sqrt(233))/2)#

#x²+11x-28# #Delta=11²-4*1*(-28)=121+112=233# #x1=(-11-sqrt(233))/2# #x2=(-11+sqrt(233))/2# So a factorized form of the trinomial is : #(x-(-11-sqrt(233))/2)(x-(-11+sqrt(233))/2)# \0/ here's our answer !

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Answer 2

Julia Adams

To factor the trinomial (x^2 + 11x - 28), you can use the factoring by grouping method:

Step 1: Multiply the coefficient of the (x^2) term (1) by the constant term (-28). This gives -28.

Step 2: Find two numbers that multiply to -28 and add up to the coefficient of the (x) term (11). The numbers are 7 and -4.

Step 3: Rewrite the middle term using the two numbers found in step 2. This gives (x^2 + 7x - 4x - 28).

Step 4: Group the terms: (x^2 + 7x) and (-4x - 28).

Step 5: Factor out the greatest common factor from each group: (x(x + 7)) and (-4(x + 7)).

Step 6: Notice that both groups have a common factor of (x + 7).

Step 7: Factor out (x + 7): ((x + 7)(x - 4)).

Therefore, the factored form of the trinomial (x^2 + 11x - 28) is ((x + 7)(x - 4)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.