How do you factor the trinomial #v^3 - 4v^2 - 45v#?

Answer 1

#v(v-9)(v+5)#

Taking #v# out as a common factor, we get:
#v(v^2-4v-45)#

Now what we have is a quadratic multiplied by a common factor. Factorising the quadratic we get the fully factored function:

#v(v-9)(v+5)#
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Answer 2

To factor the trinomial ( v^3 - 4v^2 - 45v ), you first look for the greatest common factor (GCF), which is ( v ). After factoring out ( v ), you're left with ( v(v^2 - 4v - 45) ). Then, you factor the quadratic expression ( v^2 - 4v - 45 ). This quadratic can be factored as ( (v - 9)(v + 5) ). So, the factored form of the trinomial is ( v(v - 9)(v + 5) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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