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How do you factor the trinomial #m^2-3mn+2n^2#?

Answer 1

Eva Adamson

#m^2 - 3mn + 2n^2 = (m - 2n )(m - n)#

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Answer 2

Hazel Anglin

#color(magenta)(=(m-n)(m-2n)#

#m^2−3mn+2n^2#

#=m^2-2mn-mn+2n^2#

Grouping:

#= m(m-2n)-n(m-2n)#

#color(magenta)(=(m-n)(m-2n)#

~Hope this helps! :)

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Answer 3

Eva Adamson

To factor the trinomial ( m^2 - 3mn + 2n^2 ), you need to find two binomials whose product equals the given trinomial. The general form of factoring a trinomial is ((am + bn)(cm + dn)), where the product of (a) and (c) equals (1) (since the leading coefficient of (m^2) is (1)). In this case, (ac = 1), (ad + bc = -3), and (bd = 2). By trial and error or using systematic methods like the AC method or grouping, you can find the factors that satisfy these conditions. In this specific trinomial, the factored form would be ((m - n)(m - 2n)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.