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How do you factor the trinomial #3x^2+9xy-30y^2#?

Answer 1

Eva Abramson

#3(x+5y)(x-2y)#

#"take out a "color(blue)"common factor "3#

#=3(x^2+3xy-10y^2)#

#"the factors of - 10 which sum to + 3 are + 5 and - 2"#

#=3(x+5y)(x-2y)#

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Answer 2

Kennedy Adams

To factor the trinomial (3x^2 + 9xy - 30y^2), you first look for common factors among the coefficients. In this case, the greatest common factor (GCF) is 3. Factoring out 3 from each term, you get (3(x^2 + 3xy - 10y^2)).

Next, you factor the quadratic expression (x^2 + 3xy - 10y^2). This can be factored into two binomials: ((x + 5y)(x - 2y)).

Therefore, the factored form of the trinomial (3x^2 + 9xy - 30y^2) is (3(x + 5y)(x - 2y)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.