How do you factor the trinomial #2x^2 - 5x - 3 #?
Through a bit of trial-and-error you can find that
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To factor the trinomial (2x^2 - 5x - 3), you can use the method of decomposition or the quadratic formula.
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To factor the trinomial (2x^2 - 5x - 3), we need to find two binomials whose product equals the trinomial. We can use the AC method, which involves finding two numbers that multiply to (2 \times (-3) = -6) and add to (-5). These numbers are (-6) and (1).
We then split the middle term ( -5x ) into ( -6x + 1x ), so the trinomial becomes (2x^2 - 6x + 1x - 3).
Now, we group the terms: ( (2x^2 - 6x) + (1x - 3) ).
Next, we factor by grouping: [ 2x(x - 3) + 1(x - 3) ]
Now, we can see that both terms have a common factor of ( (x - 3) ), so we can factor out ( (x - 3) ): [ (2x + 1)(x - 3) ]
So, the factored form of the trinomial ( 2x^2 - 5x - 3 ) is ( (2x + 1)(x - 3) ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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