How do you factor the trinomial #2x^2 - 5x - 3 #?

Answer 1

Through a bit of trial-and-error you can find that #2x^2-5x-3=(2x+1)(x-3)#.

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Answer 2

To factor the trinomial (2x^2 - 5x - 3), you can use the method of decomposition or the quadratic formula.

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Answer 3

To factor the trinomial (2x^2 - 5x - 3), we need to find two binomials whose product equals the trinomial. We can use the AC method, which involves finding two numbers that multiply to (2 \times (-3) = -6) and add to (-5). These numbers are (-6) and (1).

We then split the middle term ( -5x ) into ( -6x + 1x ), so the trinomial becomes (2x^2 - 6x + 1x - 3).

Now, we group the terms: ( (2x^2 - 6x) + (1x - 3) ).

Next, we factor by grouping: [ 2x(x - 3) + 1(x - 3) ]

Now, we can see that both terms have a common factor of ( (x - 3) ), so we can factor out ( (x - 3) ): [ (2x + 1)(x - 3) ]

So, the factored form of the trinomial ( 2x^2 - 5x - 3 ) is ( (2x + 1)(x - 3) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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