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How do you factor the trinomial #18a^2+48a+32#?

Answer 1

Eva Adamson

#2(3a+4)^2#

#18a^2 + 48a + 32#

#(18a^2)/2 + (48a)/2 + 32/2#

#9a^2 + 24a + 16#

16(last term) x 9(co-efficient of #a^2#) = 144

Think of two numbers that #rArr# When you multiply them = 144 #rArr# When you add them = 24 (co-efficient of #a#)

12 and 12 #rArr# 12 x 12 = 144 #rArr# 12 + 12 = 24

Replace the middle number with 12 and 12 #9a^2 + 12a + 12a + 16#

Split the expression #9a^2 + 12a----- | ----- + 12a + 16#

Factorise the two #3a(3a + 4) + 4(3a +4)#

Common factors so group #(3a + 4)(3a +4)#

#rArr# #(3a+4)^2#

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Answer 2

Hazel Anglin

To factor the trinomial (18a^2 + 48a + 32), you can start by finding the greatest common factor (GCF) of all the terms, which in this case is (2). Then, divide each term by the GCF to simplify the expression. After that, factor the resulting quadratic expression using techniques such as grouping or trial and error. Applying these steps, you can factor the trinomial as ((3a + 4)(6a + 8)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.