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How do you factor the trinomial #14x^2 – 19x – 3#?

Answer 1

#14x^2-19x-3=(7x+1)(2x-3)#

To factorize #14x^2-19x-3#, we should split the coefficient of middle term #-19# in two parts whose product is product of coefficients of other two terms, i.e. #14xx(-3)=-42#.

The pair could be #+2# and #-21# and hence

#14x^2-19x-3#

= #14x^2-21x+2x-3#

= #7x(2x-3)+1(2x-3)#

= #(7x+1)(2x-3)#

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Answer 2

Jameson Allen

To factor the trinomial (14x^2 - 19x - 3), you can use the factoring by grouping method. First, multiply the coefficient of the (x^2) term (14) by the constant term (-3) to get -42. Then, find two numbers that multiply to -42 and add up to the coefficient of the (x) term (-19). The numbers are -21 and 2. Now, rewrite the middle term (-19x) using these two numbers: (14x^2 - 21x + 2x - 3). Factor by grouping: (7x(2x - 3) + 1(2x - 3)). Factor out the common binomial factor (2x - 3): ((7x + 1)(2x - 3)). So, the factored form of (14x^2 - 19x - 3) is ((7x + 1)(2x - 3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.