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How do you factor the trinomial #12 y^2- 17y +5#?

Answer 1

Hazel Anglin

#(12y-5)(y-1)#

#12y^2-17y+5#

multiply the coeff of #y^2" & the constant"#

#12xx5=60#

find factors of #60" that add to "-17#

#-12,-5#

start by reducing the #y# term with these factors then factorise by grouping.

#12y^2-12y-5y+5#

#(12y^2-12y)-(5y-5)#

#12y(y-1)-5(y-1)#

#(12y-5)(y-1)#

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Answer 2

Kennedy Adams

To factor the trinomial (12y^2 - 17y + 5), you look for two numbers that multiply to give you (12 \times 5 = 60) and add to give you (-17). The numbers are (-12) and (-5). So, you can rewrite the trinomial as (12y^2 - 12y - 5y + 5). Now, you group the terms: ((12y^2 - 12y) + (-5y + 5)). Next, factor out the greatest common factor from each group: (12y(y - 1) - 5(y - 1)). Finally, factor out the common binomial factor (y - 1): ((12y - 5)(y - 1)). So, the factored form of (12y^2 - 17y + 5) is ((12y - 5)(y - 1)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.