How do you factor the polynomials #2nu-8u+3n-12#?
Nathan AxelNot possible; the terms contain no common factors
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Kennedy AdamsTo factor the polynomial 2nu - 8u + 3n - 12, you can factor by grouping. First, group the terms with common variables: (2nu - 8u) + (3n - 12). Then factor out the greatest common factor from each group: 2u(n - 4) + 3(n - 4). Now, you can see that both groups have a common factor of (n - 4), so factor that out: (2u + 3)(n - 4).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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