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How do you factor the monomial #-20m^5n^2# completely?

Answer 1

Abigail Allen

We can write the prime factors of #-20m^5n^2# as:

#-2 xx 2 xx 5 xx m xx m xx m xx m xx m xx n xx n#

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Answer 2

Eva Adamson

To factor the monomial -20m^5n^2 completely, you break down the coefficients and variables into their prime factors:

-20 = -1 * 2 * 2 * 5 m^5 = m * m * m * m * m n^2 = n * n

Then, you rearrange the factors to form pairs where each pair has the same base:

-20m^5n^2 = -1 * 2 * 2 * 5 * m * m * m * m * m * n * n

This can be written as:

-20m^5n^2 = (-1 * 2 * 2 * 5) * (m * m * m * m * m) * (n * n)

Finally, you express the prime factors as a product:

-20m^5n^2 = -1 * 2^2 * 5 * m^5 * n^2

So, the monomial -20m^5n^2 is factored completely as -1 * 2^2 * 5 * m^5 * n^2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.