How do you factor the expression #x^3-2x^2-9x+18#?

Answer 1

#f(x)= (x-2)(x^2-9)# = (x-2)(x-3)(x+3)

We can factorise by determining zeros of f(x). These zeros are some factors of 18. These can be determined by hit and trial method. If at least one zero is located, then remaining two can be used by factorising a quadratic.

In the present case it can be easily verified that x=2 is a zero of the polynomial. Now divide the polynomial by x-2 using long or synthetic division, the quotient got would be #x^2-9#

#f(x)= (x-2)(x^2-9)# = (x-2)(x-3)(x+3)

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Ethan Adkins

To factor the expression x^3 - 2x^2 - 9x + 18, you can first look for any common factors and then apply techniques like grouping or synthetic division if necessary. In this case, the expression can be factored as (x - 3)(x - 3)(x + 2).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.