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How do you factor the expression #x^2+ 2x -3#?

Answer 1

Avery Alexander

(x + 3 )(x - 1 )

To factor , consider the factors of the constant term - 3 which sum to give the coefficient of the x term +2

factors of - 3 are ± (1 , 3 )

The required factors are +3 and - 1 ,as they sum to +2.

#rArr x^2 + 2x - 3 = (x + 3 )(x - 1 )#

This may be confirmed by distributing the brackets.

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Answer 2

Hazel Anglin

This is a trinomial of the form #y = ax^2 + bx + c#, which is factored as #(x + m)(x + n)#

We can find the value of m and n by finding two numbers that multiply to c and that add to b. Two numbers that multiply to -3 and that add to +2 are 3 and -1:

So, when factored, the expression is #(x + 3)(x - 1)#

Practice exercises:

a) #x^2 + 7x + 12#

b) #x^2 - 7x - 12#

c) #x^2 - 7x + 12#

d) #-x^2 + 7x - 12#

d) #x^2 + 8x + 16#

e) #x^2 + 8x - 16#

f) #x^2 - 8x + 16#

g) #x^2 + 16#

h) #x^2 - 16#

Good luck!

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Answer 3

Hazel Anglin

To factor the expression x^2 + 2x - 3, you can find two numbers that multiply to -3 and add up to 2. Those numbers are 3 and -1. Then, you can rewrite the expression as (x + 3)(x - 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.