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How do you factor the expression #6x^2+7x+2#?

Answer 1

y = (2x + 1)(3x + 2)

Use the new AC Method to factor trinomial. (Socratic Search) #y = 6x^2 + 7x + 2 = #6(x + p)(x + q) Converted trinomial: #y' = x^2 + 7x + 12# Factor pairs of 12 --> (3, 4). This sum is 7 = b. #p= 3/6 = 1/2# and #q = 4/6 = 2/3.# Factored form: #y = 6(x + 1/2)(x + 2/3) = (2x + 1)(3x + 2)#

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Answer 2

Nathan Axel

To factor the expression (6x^2 + 7x + 2), you would use the factoring method. This involves finding two numbers that multiply to give you the constant term (2) and add to give you the coefficient of the linear term (7x). Those numbers are 1 and 2. Then, you split the middle term using those two numbers and factor by grouping. The factored form is ((2x + 1)(3x + 2)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.