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How do you factor the expression #16y^2 - 12y + 2#?

Answer 1

f(y) = 2(4y - 1)(2y - 1)

There is a systematic, non- guessing, new AC Method (Socratic Search) #f(y) = 16y^2 - 12y + 2 =# 16(y + p)(y + q) Converted trinomial #f'(y) = x^2 - 12y + 32 =# (x + p')(x + q') p' and q' have same sign, because ac > 0. Factor pairs of (ac = 32) --> (-4, -8) . This sum is -12 = b. Then, p' = -4 and q' = -8. Back to f(y), #p = (p')/a = -4/16 = -1/4# and #q = (q')/a = -8/16 = -1/2#. Factored form: #f(y) = 16(y - 1/4)(y - 1/2) = 2(4y - 1)(2y - 1)#

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Answer 2

Eva Adamson

To factor the expression (16y^2 - 12y + 2), you can use the quadratic formula or factoring by grouping. Since the expression cannot be factored easily, it may not factor further using integers.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.