How do you factor the expression #-14x+8+6x^2#?

Answer 1

2(x - 1)(3x - 4)

Bring the expression to standard form: #f(x) = 6x^2 - 14x + 8# Since a + b + c = 0 - One real root is (1) and the factor is (x - 1) - One real root is #(c/a = 8/6)# and the factor is #(x - 8/6)# Factor form of f(x): #f(x) = a(x - x1)(x - x2) = 6(x - 1)(x - 8/6) = (x - 1)(6x - 8) = 2(x - 1)(3x - 4)#

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Answer 2

Eva Abramson

To factor the expression -14x + 8 + 6x^2, you rearrange the terms to align them in descending order of exponents:

6x^2 - 14x + 8

Then, you look for common factors, if any, which in this case, there aren't any common factors among the terms.

Next, you can attempt to factor the quadratic trinomial:

6x^2 - 14x + 8

This can be factored as:

2(3x - 2)(x - 2)

Therefore, the factored form of the expression -14x + 8 + 6x^2 is 2(3x - 2)(x - 2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.