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How do you factor #(t+u)^3-64#?

Answer 1

Kennedy Adams

Apply the formula: (a - b)(a² + ab + b²)

#a-](t+u)^3# #b-]64#

#therefore (t+u)^3-64# #=(t+u−64){(t+u)^2+(t+u)(64)+64^2}#

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Answer 2

Abigail Allen

To factor (t+u)^3 - 64, you can use the formula for factoring the difference of cubes, which is a^3 - b^3 = (a - b)(a^2 + ab + b^2). Applying this formula:

(t+u)^3 - 64 = [(t+u) - 4][(t+u)^2 + (t+u)(4) + 4^2]

Simplify further if needed.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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