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How do you factor #t^2-5t+6#?

Answer 1

Ethan Adkins

#(t-2)(t-3)#

#"the factors of + 6 which sum to - 5 are - 2 and - 3"#

#rArrt^2-5t+6=(t-2)(t-3)#

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Answer 2

Kennedy Adams

#t^2 - 5t +6 = (t-2)(t-3)#

In a trinomial with the degree #2# and with #1# as the leading coefficient, you need to find two numbers that add up to the second term and have a product that is the third term.

In this trinomial, the sum (second term) is #-5# and the product (third term) is #6#. The numbers #-2# and #-3# satisfy the terms. Therefore, #t^2 - 5t +6 = (t-2)(t-3)#.

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Answer 3

Jace Anderson

To factor the quadratic expression (t^2 - 5t + 6), you would look for two numbers that multiply to (6) and add to (-5). These numbers are (-2) and (-3). So, the factored form of (t^2 - 5t + 6) is ((t - 2)(t - 3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.