How do you factor completely #5a^2 + b#?

Answer 1

This expression cannot be simplified further.

Unless we are given extra information (e.g. #b = -5#), then this expression cannot be factored further.
If the second term was #b^2# rather than #b#, then it would be possible to factor using Complex coefficients:
#5a^2+b^2 = (sqrt(5)a)^2-(bi)^2 = (sqrt(5)a-bi)(sqrt(5)a+bi)#
Alternatively, if we were told that #b >=0# then we could write
#5x^2+b = (sqrt(5)a)^2-(sqrt(b)i)^2 = (sqrt(5)a-sqrt(b)i)(sqrt(5)a+sqrt(b)i)#
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Answer 2

To factor completely, you look for common factors, but in this case, there aren't any. So, the expression 5a^2 + b is already factored completely.

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Answer 3

To factor completely (5a^2 + b), there isn't a simple way to factor it further without additional information or specific instructions. If you're looking to factor it over the real numbers, and assuming (a) and (b) are real numbers, then (5a^2 + b) is already in its simplest factored form. However, if (a) and (b) are variables or if you have more context or constraints, additional factoring might be possible.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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