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How do you factor completely #3x^3 + 24x^2 + 48x#?

Answer 1

Avery Alexander

#=3x(x+4)^2#

#3x^3+24x^2+48x# #=3x(x^2+8x+16)# #=3x(x^2+2x(4)+4^2)# #=3x(x+4)^2#

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Answer 2

Kennedy Adams

=#3x(x + 4)(x+4)#

Take out a common factor first. In this case #3x#

#3x^3 + 24x^2+ 48x#

=#3x(x^2 + 8x+ 16)#

=#3x(x + 4)(x+4)#

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Answer 3

Ethan Adkins

To factor completely (3x^3 + 24x^2 + 48x), first, factor out the greatest common factor, which is (3x). This leaves (3x(x^2 + 8x + 16)). Then factor the quadratic expression (x^2 + 8x + 16) as ((x + 4)^2). Therefore, the complete factorization is (3x(x + 4)^2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.