How do you factor completely #36+3x-3x^2#?

Answer 1

Factor #y = -3x^2 + 3x + 36 = -3(x^2 - x - 12)#

Factor #f(x) = x^2 - x - 12.# Compose factor pairs of (-12) --> (-2, 6)(-3, 4). This sum is 1 = -b. Then the factor are (x + 3) and (x - 4)

y equals (x + 3)(x - 4)

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Answer 2

Abigail Allen

To factor completely the expression 36 + 3x - 3x^2, first rearrange the terms in descending order of powers of x: -3x^2 + 3x + 36.

Then, factor out the greatest common factor, which is -3: -3(x^2 - x - 12).

Now, factor the quadratic expression inside the parentheses: (x - 4)(x + 3).

Therefore, the expression is factored completely as: -3(x - 4)(x + 3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.