How do you factor completely: #21x^3 + 35x^2 + 9x + 15 #?

Answer 1

Factor by grouping to find:

#21x^3+35x^2+9x+15=(7x^2+3)(3x+5)#

#21x^3+35x^2+9x+15#
#=(21x^3+35x^2)+(9x+15)#
#=7x^2(3x+5)+3(3x+5)#
#=(7x^2+3)(3x+5)#
The term #7x^2+3# has no linear factors with real coefficients since #7x^2+3 >= 3 > 0# for all #x in RR#.
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Answer 2

To factor completely the expression 21x^3 + 35x^2 + 9x + 15, you can first look for common factors, then use techniques such as grouping or polynomial long division. However, in this case, the expression cannot be factored further using basic algebraic techniques.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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