# How do you factor completely #18x^2-30x-3x+5#?

y = (6x - 1)(3x - 5)

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To factor completely the expression (18x^2 - 30x - 3x + 5), you first group the terms:

(= (18x^2 - 3x) + (-30x + 5))

Then, factor out the greatest common factor from each group:

(= 3x(6x - 1) - 1(6x - 1))

Now, you can see that both groups have a common factor of (6x - 1), so you can factor it out:

(= (3x - 1)(6x - 1))

Therefore, the expression (18x^2 - 30x - 3x + 5) factors completely to ((3x - 1)(6x - 1)).

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To factor completely (18x^2 - 30x - 3x + 5), first, group the terms:

(18x^2 - 30x - 3x + 5 = (18x^2 - 30x) + (-3x + 5))

Then, factor out the greatest common factor from each group:

(6x(3x - 5) - 1(3x - 5))

Now, notice that both terms share a common factor of (3x - 5). Factor it out:

((3x - 5)(6x - 1))

So, the completely factored form of (18x^2 - 30x - 3x + 5) is ((3x - 5)(6x - 1)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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